X^2+15x-3850=0

Solution for X^2+15x-3850=0 equation:

X^2+15X-3850=0

a = 1; b = 15; c = -3850;
Δ = b2-4ac
Δ = 152-4·1·(-3850)
Δ = 15625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15625}=125$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-125}{2*1}=\frac{-140}{2}
=-70
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+125}{2*1}=\frac{110}{2}
=55
$